-2x^2+120x-1512=0

Solution for -2x^2+120x-1512=0 equation:

-2x^2+120x-1512=0

a = -2; b = 120; c = -1512;
Δ = b2-4ac
Δ = 1202-4·(-2)·(-1512)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-48}{2*-2}=\frac{-168}{-4}
=+42
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+48}{2*-2}=\frac{-72}{-4}
=+18
$